How to Figure Half-Life from Two Measurements
The half-life of a decaying compound is the length of time required for the quantity to decrease by 50%. Radioactive isotopes of elements often decay at constant, measureable rates, and half-life is a convenient way to describe the rate at which the substance breaks down. Something with a longer half-life decays more slowly, while something with a shorter half-life decays more rapidly.
If you know the levels at two different points in time, you can use these numbers to determine the equation of exponential decay and the half-life. For a substance that decays exponentially at a constant rate, the equation for the quantity at time T is
Q(T) = ABT or equivalently
Q(T) = AekT ,
where e is the natural log base and the relation between B and K is Ln(B) = k. Whether you use the first or second equation is a matter of personal preference. Below we show how to find the exponential decay equation and half-life with an example; you can also use the convenient half-life calculator on the left.
ExampleSuppose you measure the quantity of a substance at two points in time. At time = 3 minutes, the quantity is 145 grams. Then at time = 46 minutes, the quantity is 107 grams. This gives us two pairs of (T,Q) coordinates: (3, 145) and (46, 107).
Set up the equation Q = ABT and plug in both sets of coordinates so that you get two equations in A and B:
145 = AB3
107 = AB46
You can solve this system for B by dividing the first equation by the second. This gives you
145/107 = (B3)/(B46)
145/107 = B-43
(145/107)^(-1/43) = B
0.9929573 = B
And to find A:
145 = A(0.9929573)3
145 = A(0.9790205)
148.1072 = A
So the equation of exponential decay is Q(T) = 148.1072(0.9929573)T, or Q(T) = 148.1072e-0.007067556T. To find the half-life, you set Q equal to one half of A and solve for T.
74.0536 = 148.1072(0.9929573)T
74.0536/148.1072 = 0.9929573T
0.5 = 0.9929573T
Ln(0.5) = Ln(0.9929573T)
Ln(0.5) = T(Ln(0.9929573))
Ln(0.5)/Ln(0.9929573) = T
98.07452 = T
So the half-life of of the substance is 98.07452 minutes. This means that it takes 1 hour, 38 minutes, and 4 seconds for the quantity to halve.
General FormulaThe general formula for the half-life H is
H = Ln(0.5)/Ln(B) = Ln(0.5)/k
You can also generalize this to compute the third-life, the time it takes for the substance to decrease to one third of its original level. The third-life J is given by
J = Ln(1/3)/Ln(B) = Ln(1/3)/k.
© Had2Know 2010